What the In-Crowd Wont Tell You About Premium Writing Service

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Marketing Plan For Supervive Apparel - 3427 Words

Marketing Plan Supervive Apparel 2015 Autumn/Winter Collection Executive Summary Supervive Apparel is a growing streetwear business that has been producing and manufacturing clothing aimed at males aged from 16-25 since 2012. In the two years that the business has been functioning, it has not achieved substantial growth and will need to grow to maintain a profitable business. This marketing plan is aimed at the next line of products to be released by Supervive Apparel, their Autumn/Winter collection of 2015. This Marketing Plan will go over the various aspects of marketing the Autumn/Winter collection of 2015 – †¢ Situational Analysis including strengths of the business and further opportunities the business can take, along with†¦show more content†¦This plan was designed to suggest strategies and actions that Supervive Apparel can take to help their business to significantly grow in the future, and to be making considerable profit from their endeavours in producing quality, fashionable clothing for consumers to purchase and enjoy. Situational Analysis Strengths †¢ Good customer service reputation in the business. †¢ A quality product is being produced by the business, so more customers will be attracted to the clothing/brand. †¢ The product is relevant to today’s fashion, with people already looking forward to buying the next line of clothes that Supervive Apparel will release. †¢ There is a good amount of loyal customers, who are definite buyers of the products that will be released. †¢ The business will have employees who have previously worked in fashion and clothing before, so they will be able to adapt well to selling a new line of products. †¢ Business has low costs, as people will pay a lot more for the product then it is being produced for. †¢ Online store is frequently used, with customers buying items from different continents such as North America and Europe. †¢ Designers of the product are known for their initiative approach to fashion There are a lot of strengths that Supervive Apparel has as a business, with most of their strength coming from their loyal customer base, and the product

Benefits of Cloud Accounting-Free-Samples-Myassignementhelp.com

Questions: 1.What are the Benefits and Limitation of Cloud Accounting, How would Implementation of the Cloud Computing Impact on the Corporate Strategy. Answers: Introduction Cloud accounting can be defined as an accounting system that is hosted on remote servers and can be accessed on the internet (Simkin, Norman, Rose, 2014). Cloud accounting helps record financial details for both small and large businesses more effectively compared to a manual or in-house accounting system. Benefits of Cloud Accounting Cloud accounting software helps to process financial records more accurately even with big numbers. Cloud accounting ensures that there is a backup server in more than one locations. This reduces risk of losing data in case of a cyber theft or interference (Mian, Teixeira, Koskivaara, 2011). The software enables individuals to access information anywhere. Despite of their locality differences. Cost effective. After purchasing cost, there are no additional costs. Once the server has being purchased there is no need to purchase it twice. Time management. When the user enters data for processing. He or she is assured of timely results whereby there will be no delays. Cloud accounting can also be accessed to more than three corporate users without slow or delayed services. The clients of Jones and Associates will be able use the software despite limitations like different currencies. The software is able to convert and give accurate results. Cloud accounting is able to process transactions efficiently for Jones and associate clients. Limitations of Cloud accounting system Cloud accounting requires uninterrupted internet connection in order to operate according to the users commands. Cloud accounting relies heavily on the users skills to enter data. If the user mistypes or misuses the software features. This will result to poor quality results and wastage of time. Garbage in ,garbage out (Molnar, Schechter, 2010). Cloud accounting can only be used by users who have legal rights of ownership or legal agreements to share. Cloud accounting software is expensive at initial cost .because one has to purchase expensive new hardware serves. This might scare of clients to Jones firm who will find their serves expensive. Cloud accounting software incurs costly maintenance due to new licensing and fee for the database system. Since the user needs to update or renew it. Software requires endless supply of electricity which will loss data if interrupted. Due to easy access of accounting software. This tends to limit professionals example accountants to be unemployed. Since the software has no specialized skills Impact of clound Accounting Profitability is ensured since more accountants are able to use it in book keeping , this ensures good quality results and good performance. When profitability is assured. This makes the firm grow rapidly since they are able to retain their clients. Security is high since cloud accounting has a password. So, bank feeds are safe and other transaction details are safe. Hence processing transactions efficiently for Jones and associate clients (Christauskas, Miseviciene, 2012). Cost effective. After purchasing cost, there are no additional cost . Once the server has being purchased there is no need to purchase it twice. Time management. When the user enters data for processing. He or she is assured of timely results whereby there will be no delays. Cloud accounting can also be accessed to more than three corporate users without slow or delayed services. The clients of Jones and Associates will be able use the software despite limitations like different currencies. The software is able to convert and give accurate results. Comparison of Xero, zoho books and wave accounting accounting packages features XERO ZOHO BOOKS Wave accounting GL,AR, AP AP and AR only GL, AR AND AP GL, AR and AP Digital Dashboard yes yes yes Secure Bank feeds yes no no Conclusion In summary, cloud accounting system is an improvement of in-house accounting systems and enables a decentralized accounting system. Therefore, Jones and Associates should adopt the cloud accounting system to enhance their proficiency and profitability in their business. References Christauskas, C., Miseviciene, R. (2012). Cloudcomputing based accounting for small to medium sized business. Engineering Economics, 23(1), 14-21. Molnar, D., Schechter, S. E. (2010). Self Hosting vs. Cloud Hosting: Accounting for the Security Impact of Hosting in the Cloud. In WEIS. Mian, S., Teixeira, J., Koskivaara, E. (2011). Open-source software implications in the competitive mobile platforms market. Building the e-World Ecosystem, 110-128. Romney, M. B., Steinbart, P. J. (2012). Accounting information systems. Boston: Pearson. Simkin, M. G., Norman, C. S., Rose, J. M. (2014). Core concepts of accounting information systems. John Wiley Sons.

To investigate the relationship between the velocity of a parachute and the drag force Essay Example

To investigate the relationship between the velocity of a parachute and the drag force Essay Viscosity :- The viscosity of a fluid is a measure of its resistance to flow. Viscous forces acting on bodies moving through a fluid and in fluids moving through pipes and channels. The pressure in a fluid decreases where the speed increases.Stokes Law :- An equation relating the terminal settling velocity of a smooth, rigid sphere in a viscous fluid of known density and viscosity to the diameter of the sphere when subjected to a known force field. It is used in the particle-size analysis of soils by the pipette, hydrometer, or centrifuge methods. The equation is:V = (2grà ¯Ã‚ ¿Ã‚ ½)(d1-d2)/9à ¯Ã‚ ¿Ã‚ ½whereV = velocity of fall (cm sec-à ¯Ã‚ ¿Ã‚ ½),g = acceleration of gravity (cm sec-à ¯Ã‚ ¿Ã‚ ½),r = equivalent radius of particle (cm),dl = density of particle (g cm -à ¯Ã‚ ¿Ã‚ ½),d2 = density of medium (g cm-à ¯Ã‚ ¿Ã‚ ½), andà ¯Ã‚ ¿Ã‚ ½ = viscosity of medium (dyne sec cm-à ¯Ã‚ ¿Ã‚ ½).A falling object has an acceleration equal to g, provided air resistance is negligible. If air resistance is significant, the force due to air resistance drags on the object. This drag force increases as the object speeds up, until the force becomes equal and opposite to its weight. The acceleration becomes zero because the resultant force on the object becomes zero. The speed therefore becomes constant; this value is referred to as the Terminal Velocity.TaskTo investigate the effect of a change in mass on the time taken for a parachute to fall a set distance.Other variables that could be investigated are:à ¯Ã‚ ¿Ã‚ ½ Surface area of the parachuteà ¯Ã‚ ¿Ã‚ ½ Length of string (between the parachute and mass), which might control the volume of air under the parachute.à ¯Ã‚ ¿Ã‚ ½ Distribution of mass, i.e. perhaps on the parachute itself as opposed to on string attached to the parachute (this of course would not be a continuous variable so it would not be of great value).ApparatusA square of bin liner, thread, sticky tape, plasticene, and weighing scales.MethodOne parachute w as assembled using a square of bin liner, thread and sticky tape. The thread was tied in such a way that plasticene masses could be attached. For each mass, the experiment was performed three times and after completion, the entire investigation was repeated. The actual experiments consisted of timing how long the parachute took to travel from the ceiling to the floor, a distance of 2.85 metres. The measurements were taken in grams and then converted into Newtons for more accurate results.In order to make this a fair test I am going to keep a number of things constant, e.g., the bin liner parachute, the length of the string, the distance for it to fall, the surface area of the parachute, and the distribution of mass.DiagramPredictionsà ¯Ã‚ ¿Ã‚ ½ The larger the mass, the shorter the time because when the mass is larger the parachute accelerates to a higher speed due to the terminal velocity being higher.TheoryVelocity = DistanceTimeAcceleration = Increase in VelocityTimeResultsExperi ment 1Mass (N) Time 1 (s) Time 2 (s) Time 3 (s) Average Time (s) Average Velocity (m/s)* Average Acceleration (m/s2)0.02 3.35 3.29 3.31 3.32 0.86 0.260.04 2.17 2.35 2.18 2.23 1.28 0.570.06 1.72 1.88 1.64 1.75 1.63 0.930.08 1.58 1.65 1.62 1.62 1.76 1.090.10 1.46 1.41 1.23 1.37 2.08 1.520.12 1.26 1.29 1.31 1.29 2.21 1.710.14 1.11 1.27 1.08 1.15 2.48 2.160.16 1.15 1.13 1.04 1.11 2.57 2.320.18 1.04 1.18 1.05 1.09 2.61 2.390.20 1.03 0.97 1.10 1.04 2.74 2.63Experiment 2Mass (N) Time 1 (s) Time 2 (s) Time 3 (s) Average Time (s) Average Velocity (m/s)* Average Acceleration (m/s2)0.02 2.78 2.32 3.28 2.79 1.02 0.370.04 2.18 2.30 1.67 2.05 1.39 0.680.06 1.57 1.40 1.50 1.49 1.91 1.280.08 1.09 1.14 1.25 1.16 2.46 2.120.10 1.19 1.31 1.29 1.26 2.26 1.790.12 1.13 1.20 1.14 1.16 2.46 2.120.14 1.09 1.07 1.13 1.10 2.59 2.350.16 0.91 1.08 1.10 1.03 2.77 2.690.18 0.88 1.01 1.06 0.98 2.91 2.970.20 0.93 0.97 1.00 0.97 2.94 3.03Averages Over Experiments 1 and 2Mass (N) Average Time (s) Average Velocity (m/ s)* Average Acceleration (m/s2)0.02 3.06 0.93 0.300.04 2.14 1.33 0.620.06 1.62 1.76 1.090.08 1.39 2.05 1.470.10 1.32 2.16 1.640.12 1.23 2.32 1.890.14 1.13 2.52 2.230.16 1.07 2.66 2.490.18 1.04 2.74 2.630.20 0.97 2.94 3.03Notes* This was calculated using the formula above (in the Theory section) using the Average Time. Unfortunately, in this case, it is not possible (without further study into complex formulae) to calculate the actual change in velocity due to the fact that the finishing velocity, or in this case the terminal velocity, remains unknown. Therefore, in order to give a very rough idea of the average acceleration, the average velocity was used as the finishing velocity and, obviously, 0 m/s used as the starting velocity (which in this case is correct).Analysisà ¯Ã‚ ¿Ã‚ ½ The first prediction, albeit rather basic, was correct and, although it was not tested, it is safe to presume that this is due to the fact that when the mass is larger, so is the terminal velocity. This means that the parachute can accelerate to a higher velocity resulting in a shorter time.à ¯Ã‚ ¿Ã‚ ½ As can be seen from the graph above it can be seen that the drop in time is rather large to begin with but gets smaller as the mass increases. This cervical result leads one to believe that there is a limit to the terminal velocity. This would imply that once a larger mass is added, a terminal terminal velocity is achieved beyond which a parachute cannot accelerate. This is presumably due to the lesser effect of air resistance at higher masses.à ¯Ã‚ ¿Ã‚ ½ The same pattern can be seen average velocities, but obviously going up rather than down, but to a lesser extent.à ¯Ã‚ ¿Ã‚ ½ The mass is directly proportional to the velocity (as the mass increases the speed increases) , and the velocity and mass is indirectly proportional to the time ( as the speed and mass increases the time decreases).Evaluationà ¯Ã‚ ¿Ã‚ ½ As was said in the Notes section above, it would be highly preferable to be able to calculate the final velocity, and even better the terminal velocity. The final velocity could be calculated with the use of computer sensors to measure the velocity in the last, say, 10cm. In order to calculate the terminal velocity it would be sensible to increase the distance travelled in order to ensure that the parachute does indeed reach terminal velocity before the velocity at the end is measured.à ¯Ã‚ ¿Ã‚ ½ As far as inaccuracies are concerned, it is obvious to see, from the Average Times graph, that the most problematic results are those measured for a mass of 0.08 N. Fortunately, they even out to provide a good average curve.à ¯Ã‚ ¿Ã‚ ½ Another problem could be the results for a mass of 0.20 N where you can see that the results seem to converge as opposed to following the otherwise reasonably error-free curve.à ¯Ã‚ ¿Ã‚ ½ Lastly, it must be further re-iterated that the Average Accelerations, and to a lesser extent the Average Velocities, use very inaccurate results due to the fact that the final velocity, and therefore the acceleration, is unknown. Therefore, the graphs of those results show very little of value other than to highlight the aforementioned inaccuracies, because they show up much more on those graphs.Conclusionsà ¯Ã‚ ¿Ã‚ ½ This theory could be proved, as well as the terminal terminal velocity calculated by using the usual mechanics formulae:i) s = ut + 1/2at2ii) v2 = u2 + 2asiii) s = (u + v)2Unfortunately, without knowledge of the terminal velocity, or the real acceleration, this cant be done properly. However, to give a rough idea of how it could be used, the test is detailed below:In an attempt to acquire the most accurate results possible, albeit a futile attempt, the third formula will be used and the average velocity used in place of the terminal velocity.1) To begin with, try the first set of results, i.e. a mass of 0.02 N:s = (0 + 0.93)2 s = 0.465Quite obviously, this distance is nowhere near the actual distance o f 2.85m but, of course, it shouldnt be because with such a small mass, air resistance is still playing a major part.2) Next, the results for a mass of 0.12 N will be tried:s = (0 + 2.32)2 s = 1.16Again, this is nowhere near the actual distance but it is getting closer.3) Lastly, the results for the last mass, 0.20 N, will be tried:s = (0 + 2.94)2 s = 1.47It would appear then, in conclusion, that this test was a failure. The question is, though, is this because of the fact that the final velocity is obviously false, or because this is not the way to go about finding the terminal terminal velocity, which of course may not exist. In all likelihood, however, looking at the results, it does exist but without the actual values for the final, or terminal, velocity, it is difficult to prove its existence.